document.write( "Question 1015126: During last year the number of students in a school increased by 100%. This year, the number of students increased by 150%. WHat percent of the number of students now was the number of student two years ago? \n" ); document.write( "
Algebra.Com's Answer #631472 by Boreal(15235)\"\" \"About 
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year 1=x
\n" ); document.write( "year 2=2x
\n" ); document.write( "increase is x/x=100%
\n" ); document.write( "year 3 is 5x
\n" ); document.write( "increase is 3x
\n" ); document.write( "Another way to get year 3 is to multiply year 2 by 1.5
\n" ); document.write( "original amount is 2x (the original amount is the most recent year)
\n" ); document.write( "Dividing, one gets 1.5 or 150%.\r
\n" ); document.write( "\n" ); document.write( "It is 5 times as much as 2 years before.
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