document.write( "Question 1015119: The perimeter of a rectangle is 90 yards. What is the perimeter of a rectangle that has twice the width and twice the height of the first rectangle?\r
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Algebra.Com's Answer #631440 by ayomidehos(1)\"\" \"About 
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Perimeter = distance round an object
\n" ); document.write( "Going round a rectangle starting from any of its corners you get a perimeter equal to twice the width and twice the height of the rectangle.
\n" ); document.write( "So, in equation form the perimeter of a rectangle is:
\n" ); document.write( "perimeter = 2(width + height)
\n" ); document.write( "For the first rectangle;
\n" ); document.write( "90 = 2(width + height)
\n" ); document.write( "width + height = 90/2 = 45
\n" ); document.write( "Let us use w to represent its width and h to represent its height. Then
\n" ); document.write( "w + h = 45\r
\n" ); document.write( "\n" ); document.write( "For the second rectangle;
\n" ); document.write( "width = 2w
\n" ); document.write( "height = 2h
\n" ); document.write( "width + height = 2w + 2h
\n" ); document.write( " = 2(w +h)
\n" ); document.write( " = 2(45)
\n" ); document.write( " = 90
\n" ); document.write( "perimeter = 2(width + height)
\n" ); document.write( " = 2(90)
\n" ); document.write( " = 180
\n" ); document.write( "Therefore the perimeter of the second rectangle is 180 yards\r
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