document.write( "Question 1015101: 3 men can do a job for 12 days. If 2 of the men work twice faster than the 3rd, how long would it take one of the faster men to do the job? \n" ); document.write( "
Algebra.Com's Answer #631408 by josgarithmetic(39632)\"\" \"About 
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Let r be the slow man rate and then 2r is the fast man rate.\r
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\n" ); document.write( "\n" ); document.write( "You have one slow man and two fast men, and combined, this group rate is \"r%2B2r%2B2r=5r\".\r
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\n" ); document.write( "\n" ); document.write( "The group of men can do 1 job in 12 days;
\n" ); document.write( "\"%285r%29%2A12=1\".\r
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\n" ); document.write( "\n" ); document.write( "\"r=1%2F%285%2A12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"r=1%2F60\", meaning the slow man does 1 job in 60 days.\r
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\n" ); document.write( "\n" ); document.write( "Either of the FASTER men will simply need HALF those number of days for the 1 job, meaning 30 days.
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