document.write( "Question 1015053: The class ran m feet at z feet per minute and arrived at lunch 3 minutes late. How fast should they have run to have arrived on time? ---Any help is greatly appreciated :) \n" ); document.write( "
Algebra.Com's Answer #631389 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! The class ran m feet at z feet per minute and arrived at lunch 3 minutes late. How fast should they have run to have arrived on time? \n" ); document.write( ": \n" ); document.write( "let s = speed required to arrive on time \n" ); document.write( "write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "slow time - normal time = 3 min \n" ); document.write( " \n" ); document.write( "multiply equation by sz, cancel the denominators \n" ); document.write( "ms - mz = 3sz \n" ); document.write( "solve for s \n" ); document.write( "ms - 3sz = mz \n" ); document.write( "Factor out s \n" ); document.write( "s(m - 3z) = mz \n" ); document.write( "s = \n" ); document.write( " \n" ); document.write( " |