document.write( "Question 1015053: The class ran m feet at z feet per minute and arrived at lunch 3 minutes late. How fast should they have run to have arrived on time? ---Any help is greatly appreciated :) \n" ); document.write( "
Algebra.Com's Answer #631389 by ankor@dixie-net.com(22740)\"\" \"About 
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The class ran m feet at z feet per minute and arrived at lunch 3 minutes late. How fast should they have run to have arrived on time?
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\n" ); document.write( "let s = speed required to arrive on time
\n" ); document.write( "write a time equation; time = dist/speed
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\n" ); document.write( "slow time - normal time = 3 min
\n" ); document.write( "\"m%2Fz\" - \"m%2Fs\" = 3
\n" ); document.write( "multiply equation by sz, cancel the denominators
\n" ); document.write( "ms - mz = 3sz
\n" ); document.write( "solve for s
\n" ); document.write( "ms - 3sz = mz
\n" ); document.write( "Factor out s
\n" ); document.write( "s(m - 3z) = mz
\n" ); document.write( "s = \"%28mz%29%2F%28%28m-3z%29%29\"; the running speed to arrive on time
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