document.write( "Question 1015062: Hello! I'm having a hard time figuring out how to set up the equations for this problem:
\n" ); document.write( "A speed boat traveled two hours with a 4km/h current before turning around. The return trip against the same current took 3 hours. Find the speed of the boat in still water.\r
\n" ); document.write( "\n" ); document.write( "Thanks for your help!
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Algebra.Com's Answer #631380 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+d+\" = distance of the one-way trip in km
\n" ); document.write( "Let \"+s+\" = the speed of the boat in still water in km/hr
\n" ); document.write( "--------------------
\n" ); document.write( "Equation for traveling with the current:
\n" ); document.write( "(1) \"+d+=+%28+s+%2B+4+%29%2A2+\"
\n" ); document.write( "Equation for traveling against the current:
\n" ); document.write( "(2) \"+d+=+%28+s+-+4+%29%2A3+\"
\n" ); document.write( "---------------------
\n" ); document.write( "(1) \"+d+=+2s+%2B+8+\"
\n" ); document.write( "(1) \"+d+-+2s+=+8+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+=+3s+-+12+\"
\n" ); document.write( "(2) \"+-d+%2B+3s+=+12+\"
\n" ); document.write( "--------------------
\n" ); document.write( "Add (1) and (2)
\n" ); document.write( "(1) \"+d+-+2s+=+8+\"
\n" ); document.write( "(2) \"+-d+%2B+3s+=+12+\"
\n" ); document.write( "-------------------
\n" ); document.write( "\"+s+=+20+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+d+-+2s+=+8+\"
\n" ); document.write( "(1) \"+d+-+2%2A20+=+8+\"
\n" ); document.write( "(1) \"+d+=+48+\"
\n" ); document.write( "The speed of the boat in still water is 20 km/hr
\n" ); document.write( "-----------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+%28+s+%2B+4+%29%2A2+\"
\n" ); document.write( "(1) \"+48+=+%2820+%2B+4+%29%2A2+\"
\n" ); document.write( "(1) \"+48+=+24%2A2+\"
\n" ); document.write( "(1) \"+48+=+48+\"
\n" ); document.write( "OK
\n" ); document.write( "(2) \"+d+=+%28+s+-+4+%29%2A3+\"
\n" ); document.write( "(2) \"+48+=+%28+20+-+4+%29%2A3+\"
\n" ); document.write( "(2) \"+48+=+16%2A3+\"
\n" ); document.write( "(2) \"+48+=+48+\"
\n" ); document.write( "OK
\n" ); document.write( "
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