document.write( "Question 1015023: If (x+1), (-2x+4) and (x+15) are 3 consecutive terms of an arithmetic sequence, determine x and the next 2 terms. \n" ); document.write( "

Algebra.Com's Answer #631357 by ikleyn(52794) $\"\"$ $\"About$

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\n" ); document.write( "If (x+1), (-2x+4) and (x+15) are 3 consecutive terms of an arithmetic sequence, determine x and the next 2 terms.
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document.write( "In arithmetic progression the difference between consecutive terms is a constant value. \r\n" );
document.write( "So, make a difference of the second and first terms and equals it to the difference between the third and the second terms.\r\n" );
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document.write( "Your equation is \r\n" );
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document.write( "(-2x +4) - (x+1) = (x+15) - (-2x+4).\r\n" );
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document.write( "Simplify and solve it:\r\n" );
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document.write( "-3x + 3 = 3x + 11,\r\n" );
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document.write( "-6x = 8,\r\n" );
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document.write( "x =  = .\r\n" );
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document.write( "The terms are \r\n" );
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document.write( "1-st:  x+1 =  = ,\r\n" );
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document.write( "2-nd:  -2x+4 =  =  = ,\r\n" );
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document.write( "3-rd:  x + 15 =  = .\r\n" );
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document.write( "These are really the terms of the arithmetic progression with the difference  = 7.\r\n" );
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document.write( "Now you can easily calculate the 4-th and 5-th terms. \r\n" );
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