document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014097>Question 1014097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Adnan scores 45% of the marks in an exam and passess by 5 marks.Taimur scores 48% of the marks in the same exam and passes by 32 marks.What are the passing marks in the exam? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631266 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631266\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let t = maximum marks available, and p = passing marks.\r<BR>\n" );
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document.write( "Then from the first sentence, we get\r<BR>\n" );
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document.write( "0.45t = p + 5.      (1)\r<BR>\n" );
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document.write( "From the 2nd sentence we obtain\r<BR>\n" );
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document.write( "0.48t = p + 32.     (2)\r<BR>\n" );
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document.write( "subtracting (1) from (2), we get\r<BR>\n" );
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document.write( "0.03t = 27\r<BR>\n" );
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document.write( "t=27/0.03 = 900, the maximum marks.\r<BR>\n" );
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document.write( "Hence, p = 0.45*900 - 5 = 400, by using (1)\r<BR>\n" );
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document.write( "Therefore the passing mark is 400.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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