document.write( "Question 1014707: If A+B+C=π then establish the given relation
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document.write( "(sin2A+sin2B+sin2C)/(4cosA/2 cosB/2 cosC/2)=8 sinA/2.sinB/2.sinC/2 \n" );
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Algebra.Com's Answer #631219 by robertb(5830)![]() ![]() You can put this solution on YOUR website! Prove first that\r \n" ); document.write( "\n" ); document.write( "sin2A + sin2B + sin2C = 4sinA*sinB*sinC. \r \n" ); document.write( "\n" ); document.write( "sin2A + sin2B + sin2C \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= sin2A(1 - cos2B) + sin2B(1 - cos2A) \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "=4sinAsinB(cosAsinB+sinAcosB) \n" ); document.write( "=4sinAsinBsin(A+B) \n" ); document.write( "= \n" ); document.write( "=4sinAsinBsinC\r \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( "= \n" ); document.write( "the main result follows. \n" ); document.write( " |