document.write( "Question 1014893: Find two consecutive odd integers such that their product is 95 more than 5 times their sum. \n" ); document.write( "
Algebra.Com's Answer #631218 by frcasem(2)\"\" \"About 
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Let x = be the first odd integer
\n" ); document.write( "x+ 2 = be the second odd integer\r
\n" ); document.write( "\n" ); document.write( "product of the integers: x(x+2)
\n" ); document.write( "sum of the integers: x+x+2 = 2x +2\r
\n" ); document.write( "\n" ); document.write( "Product of integers = 95 more than 5 times their sum
\n" ); document.write( "x(x + 2) = 5 (2x + 2) + 95, using distributive property
\n" ); document.write( "x^2+2x = 10x+10+95, combine similar terms and equate to 0
\n" ); document.write( "x^2 - 8x - 105 = 0, solve by factoring
\n" ); document.write( "(x - 15)(x+7) = 0
\n" ); document.write( "Using zero product property
\n" ); document.write( "x - 15 = 0; x = 15
\n" ); document.write( "x+ 7 = 0; x = -7
\n" ); document.write( "If x = 15, then x+2 = 17.
\n" ); document.write( "If x= -7 , then x+2 = -5 \n" ); document.write( "
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