document.write( "Question 1014794: A car traveled at a steady speed for 105 miles. Because of traffic, the driver had to cut her speed in half for the next 42 miles. The total time for the trip was 2 hours and 42 minutes. Find the original speed. \n" ); document.write( "
Algebra.Com's Answer #631203 by robertb(5830)\"\" \"About 
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Let x = constant original speed, in miles per hour.\r
\n" ); document.write( "\n" ); document.write( "Then for first 105 miles, with a rate of x mph, the time traveled was 105/x hours. (From the formula t = distance/speed.)\r
\n" ); document.write( "\n" ); document.write( "The last 42 miles was traveled at a rate of x/2 mph as given, so the time traveled is \"42%2F%28x%2F2%29\", or 84/x hours.\r
\n" ); document.write( "\n" ); document.write( "Hence, as mentioned in the problem, \"105%2Fx%2B+84%2Fx+=+2.7\"\r
\n" ); document.write( "\n" ); document.write( "\"189%2Fx+=+2.7\"
\n" ); document.write( "\"x%2F189+=+1%2F2.7\"
\n" ); document.write( "\"x+=+189%2F2.7\", after cross-multiplication.\r
\n" ); document.write( "\n" ); document.write( "Thus, x = 70 mph, the original speed.
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