document.write( "Question 1014890: y+1=x -2x+3y=2 \n" ); document.write( "

Algebra.Com's Answer #631202 by ikleyn(52810) $\"\"$ $\"About$

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document.write( " y + 1 = x     (1)\r\n" );
document.write( "-2x + 3y = 2.  (2)\r\n" );
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document.write( "Probably, you want to solve this system although you do not say it directly and explicitly.\r\n" );
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document.write( "For it, substitute the expression x = y+1 from (1) into equation (2).\r\n" );
document.write( "By doing so, you will exclude the unknown x and will get a single equation for the unknown y:\r\n" );
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document.write( "-2*(y+1) + 3y = 2,  or \r\n" );
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document.write( "-2y - 2 + 3y = 2,   or\r\n" );
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document.write( "y = 2 + 2 = 4.\r\n" );
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document.write( "Hence, x = y + 1 = 5.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Next time please write these words \"Please help me solve . . . \" or something equivalent at the beginning of your post, OK?\r
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\n" ); document.write( "\n" ); document.write( "They are \"magic words\" . . . \r
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