document.write( "Question 1014810: A coffee manufacturer wants to market a new blend of coffee that sells for $3.90 per pound by mixing two coffees that sell for $2.75 and $5 per pound, respectively. what amount of each coffee should be blended to obtain the desired mixture? (hint: Assume that the total weight of the desired blend is 100 pounds) \n" ); document.write( "
Algebra.Com's Answer #631131 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = pounds of $2.75/ lb coffee needed
\n" ); document.write( "Let \"+b+\" = pounds of $5.00/ lb coffee needed
\n" ); document.write( "Assume total of 100 pounds of blend
\n" ); document.write( "----------------------------------
\n" ); document.write( "(1) \"+a+%2B+b+=+100+\"
\n" ); document.write( "(2) \"+%28+2.75a+%2B+5b+%29+%2F+100+=+3.9+\"
\n" ); document.write( "---------------------------------
\n" ); document.write( "(2) \"+2.75a+%2B+5b+=+390+\"
\n" ); document.write( "(2) \"+275a+%2B+500b+=+39000+\"
\n" ); document.write( "(2) \"+11a+%2B+20b+=+1560+\"
\n" ); document.write( "Multiply both sides of (1) by \"+11+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+11a+%2B+20b+=+1560+\"
\n" ); document.write( "(1) \"+-11a+-+11b+=+-1100+\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"+9b+=+460+\"
\n" ); document.write( "\"+b+=+51.11+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+a+%2B+b+=+100+\"
\n" ); document.write( "(1) \"+a+=+48.89+\"
\n" ); document.write( "48.89 pounds of $2.75/ lb coffee are needed
\n" ); document.write( "51.11 pounds of $5.00/ lb coffee are needed
\n" ); document.write( "---------------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+2.75a+%2B+5b+%29+%2F+100+=+3.9+\"
\n" ); document.write( "(2) \"+%28+2.75%2A48.89+%2B+5%2A51.11+%29+%2F+100+=+3.9+\"
\n" ); document.write( "(2) \"+%28+134.45+%2B+255.55+%29+%2F+100+=+3.9+\"
\n" ); document.write( "(2) \"+390+=+390+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );