document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014760>Question 1014760</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6 sqrt[6](2 sqrt[3]+5 sqrt[2] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631103 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631103\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That is 12 sqrt (18)+30 sqrt(12)<BR>\n" );
document.write( "sqrt (18)=3 sqrt (2); sqrt 12=2 sqrt (3)<BR>\n" );
document.write( "36 sqrt(2)+60 sqrt(3)<BR>\n" );
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document.write( "Rough check: <BR>\n" );
document.write( "14.7(3.5+7)=14.7(10.5)=about 154.<BR>\n" );
document.write( "36 sqrt (2) is about 50<BR>\n" );
document.write( "60 sqrt (3) is about 103<BR>\n" );
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