document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014729>Question 1014729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> g(x) = 4x – 4 <BR>\n" );
document.write( "h(x) = 2x + 5<BR>\n" );
document.write( "find g(3) + h(3)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #631030 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=631030\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if g(x) = 4x - 4, then g(3) means to replace x with 3 and evaluate the expression.<BR>\n" );
document.write( "you will get g(3) = 4*3 - 4 = 12 - 4 = 8.\r<BR>\n" );
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document.write( "if  h(x) = 2x + 5, then h(3) means to replace x with 3 and evaluate the expression.<BR>\n" );
document.write( "you will get h(3) = 2*3 + 5 = 6 + 5 = 11.\r<BR>\n" );
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document.write( "g(3) + h(3) becomes 8 + 11 = 19.\r<BR>\n" );
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document.write( "you could also have combined them when they were still in variable form.\r<BR>\n" );
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document.write( "when g(x) = 4x - 4 and h(x) = 2x + 5, then g(x) + h(x) = (4x - 4) + (2x + 5).\r<BR>\n" );
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document.write( "remove parentheses to get g(x) + h(x) = 4x - 4 + 2x + 5.\r<BR>\n" );
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document.write( "combine like terms to get g(x) + h(x) = 6x + 1.\r<BR>\n" );
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document.write( "let's call g(x) + h(x) some other name, such as k(x).\r<BR>\n" );
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document.write( "you get k(x) = g(x) + h(x) = 6x + 1.\r<BR>\n" );
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document.write( "this results in k(x) = 6x + 1.\r<BR>\n" );
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document.write( "when k(x) = 6x + 1, then k(3) = 6*3 + 1 = 18 + 1 = 19.\r<BR>\n" );
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document.write( "you get the same solution whether you evaluate them first and then combine, or whether you combine them first and then evaluate.\r<BR>\n" );
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document.write( "your solution is that g(3) + h(3) = 19.\r<BR>\n" );
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