document.write( "Question 1741: The lengths of the sides of three squares are s, s+1, and s+2 . If their total area is 365 cm squared, find their total perimeter. \n" ); document.write( "

Algebra.Com's Answer #631 by usyim88hk(158) $\"\"$ $\"About$

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s^2 = the area of the first square
\n" ); document.write( "(s+1)^2 = the area of the second square
\n" ); document.write( "(s+2)^2 = the area of the third square
\n" ); document.write( "s^2 + (s+1)^2 + (s+2)^2 = the area of the sum of the three squares
\n" ); document.write( "s^2 + s^2 + 2s + 1 + s^2 + 4s + 4 = 365
\n" ); document.write( "3s^2 + 6s -360 = 0
\n" ); document.write( "Use the quardratic formula
\n" ); document.write( " $\"x=%286%2B-sqrt%286%5E2-4%283%29%28-360%29%29%29%2F%282%283%29%29\"$
\n" ); document.write( " $\"x=%286%2B-sqrt%284356%29%29%2F6\"$
\n" ); document.write( " $\"x=%286%2B-66%29%2F6\"$
\n" ); document.write( "x = 72/6 or -60/6
\n" ); document.write( "x = 12 or -10
\n" ); document.write( "Since length can not be a negative number, 12 is the answer
\n" ); document.write( "s = 12
\n" ); document.write( "s+1 = 13
\n" ); document.write( "s+2 = 14
\n" ); document.write( " \n" ); document.write( "

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