document.write( "Question 1014678: The Perimeter of a certain playing field is 222ft the field is a rectangle, and the length is 49 ft longer then the width. Find the dimensions.\r
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document.write( "Personal note: If I done my math correct, I think you are suppose to add 49+49 which gets 98. subtract 98 from 222 ft and then divide it by 49. which equals to 2.530612245, now if you times that with 49 you should get 122.5.
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document.write( "I been working on this problem for the past couple of days, and maybe I'm either overthinking it or I'm just doing it wrong. \n" );
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Algebra.Com's Answer #630990 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "W=width; L=length=W+49 \n" ); document.write( ". \n" ); document.write( "P=2(L+W) \n" ); document.write( "222 ft=2(L+W) Divide each side by 2 \n" ); document.write( "111 ft=L+W . Substitute for L \n" ); document.write( "111 ft=(W+49ft)+W \n" ); document.write( "111ft=2W+49ft Subtract 49 ft from each side. \n" ); document.write( "62ft=2W \n" ); document.write( "31ft=W \n" ); document.write( "ANSWER 1: The width is 31 feet. \n" ); document.write( ". \n" ); document.write( "L=W+49ft=31ft+49ft=80ft \n" ); document.write( "ANSWER 2: The length is 80 feet. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "P=2(L+W) \n" ); document.write( "222ft=2(80ft+31ft) \n" ); document.write( "222ft=2(111ft) \n" ); document.write( "222ft=222ft \n" ); document.write( " \n" ); document.write( " |