document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014678>Question 1014678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Perimeter of a certain playing field is 222ft  the field is a rectangle, and the length is 49 ft longer then the width.  Find the dimensions.\r<BR>\n" );
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document.write( "Personal note: If I done my math correct, I think you are suppose to add 49+49 which gets 98. subtract 98 from 222 ft and then divide it by 49. which equals to 2.530612245, now if you times that with 49 you should get 122.5. <BR>\n" );
document.write( "I been working on this problem for the past couple of days, and maybe I'm either overthinking it or I'm just doing it wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630987 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The Perimeter of a certain playing field is 222ft the field is a rectangle, and the length is 49 ft longer then the width. Find the dimensions<BR>\n" );
document.write( "2l+2w = 222 Your problem says that l= w+49, so substitute:<BR>\n" );
document.write( "2(w+49)+2w = 222<BR>\n" );
document.write( "2w+98+2w= 222 Add w on left and subtract 98 on both sides:<BR>\n" );
document.write( "4w= 124 Divide both sides by 4:<BR>\n" );
document.write( "w= 31 and the length:<BR>\n" );
document.write( "31+49= 80 </SPAN>\n" );
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