document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014667>Question 1014667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> P is parallel to q <BR>\n" );
document.write( "m angle 1 =(6x+y-4) <BR>\n" );
document.write( "m angle 2 = (x+9y+1) <BR>\n" );
document.write( "m angle 3 = (11x+2) <BR>\n" );
document.write( " Heres the picture\r<BR>\n" );
document.write( "\n" );
document.write( "https://lh3.googleusercontent.com/-mz0tZ0ejAxJrnC8P-0TMrKQTsuvtSz_8G4qfVXwu3FvV0onrNLYM6hufqIVZrylmKGycw=s136\r<BR>\n" );
document.write( "\n" );
document.write( "A.  Set up an equation(s) to find x and y.\r<BR>\n" );
document.write( "\n" );
document.write( "B.  Show all work and solve for x and y.\r<BR>\n" );
document.write( "\n" );
document.write( "C.  Use these values to find the values of angles 1, 2, and 3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630958 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Angle 1 and angle 2 are of equal measure, because they are alternate interior angles.  This means  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6x%2By-4=x%2B9y%2B1 ALIGN=MIDDLE  ALT=\"6x%2By-4=x%2B9y%2B1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Sum of the measures of angles 2 and 3 is 180 degrees because they are supplementery.  This means  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B9y%2B1%2B11x%2B2=180 ALIGN=MIDDLE  ALT=\"x%2B9y%2B1%2B11x%2B2=180\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Do you now know what to do? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );