document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014664>Question 1014664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble setting up the equation for the following problem:\r<BR>\n" );
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document.write( "A plane flies 450 miles with the wind in 3 hours. Flying back against the wind, the plane takes 5 hours to make the trip What was the rate of the plane in still air? What was the rate of the wind?\r<BR>\n" );
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document.write( "Thanks so much for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630956 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Rate going=450 mi/3 hours= 150 mi/hr<BR>\n" );
document.write( "Rate returning=450 mi/5 hours= 90 mi/hr<BR>\n" );
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document.write( "R=rate in still air; W=wind speed<BR>\n" );
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document.write( "Rate going =R+W=150mph<BR>\n" );
document.write( "Rate back = R-W=90 mph  Subtract this from equation above.<BR>\n" );
document.write( "2W=60 mph<BR>\n" );
document.write( "W=30 mph<BR>\n" );
document.write( "ANSWER 1: Wind speed was 30 mph <BR>\n" );
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document.write( "R+W=150 mph<BR>\n" );
document.write( "R=150mph-W<BR>\n" );
document.write( "R=150mph-30mph=120mph<BR>\n" );
document.write( "ANSWER 2: The speed of the plane in still air is 120 mph.<BR>\n" );
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document.write( "CHECK:<BR>\n" );
document.write( "R-W=90 mph<BR>\n" );
document.write( "120mph-30mph=90mph<BR>\n" );
document.write( "90mph=90mph<BR>\n" );
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document.write( " </SPAN>\n" );
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