document.write( "Question 1014570: If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation
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document.write( "h= -16^2 + vt +s,
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document.write( "where h is in feet. If the object is propelled from a height of
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document.write( "8
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document.write( "feet with an initial velocity of
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document.write( "96
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document.write( "feet per second, its height h is given by the equation
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document.write( "h= -16t^2+96t+8.
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document.write( "After how many seconds is the height
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document.write( "148
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document.write( "feet? \n" );
document.write( "
Algebra.Com's Answer #630948 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation \n" ); document.write( "h= -16^2 + vt +s, where h is in feet. \n" ); document.write( " If the object is propelled from a height of 8 feet \n" ); document.write( " with an initial velocity of 96 feet per second, \n" ); document.write( " its height h is given by the equation: h= -16t^2+96t+8. \n" ); document.write( "After how many seconds is the height 148 feet? \n" ); document.write( ": \n" ); document.write( "We can write the equation: \n" ); document.write( "-16t^2 + 96t + 8 = 148 \n" ); document.write( "-16t^2 + 96t + 8 - 148 = 0 \n" ); document.write( "-16t^2 + 96t - 140 = 0 \n" ); document.write( "simplify, divide by -4 \n" ); document.write( "4t^2 - 24t + 35 = 0 \n" ); document.write( "solve for t using the quadratic formula; a=4; b=-24; c=35 \n" ); document.write( "Two solutions \n" ); document.write( "t = 2.5 seconds to reach a height of 148 ft on the way up \n" ); document.write( "and \n" ); document.write( "t = 3.5 seconds to descend to 148 ft on the way down \n" ); document.write( " \n" ); document.write( "looks like this graphically, green line is 148ft \n" ); document.write( " |