document.write( "Question 1014614: I need help please! Thanks!
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document.write( " http://www.math.info/image/419/parallelogram.jpg
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document.write( "(Using the link above is what it looks like)
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document.write( "Given: parallelogram EFGH, with diagonals EG and HF
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document.write( "Prove: triangle EFK = triangle GHK
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document.write( "***On my paper A is E, B is F, D is H, C is G and E is K*****
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document.write( "*The pic is for a visual* \n" );
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Algebra.Com's Answer #630905 by solver91311(24713) You can put this solution on YOUR website! \n" ); document.write( "Use the following theorems:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Theorem 1: A quadrilateral is a parallelogram if and only if the diagonals bisect each other.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Theorem 2: Vertical angles are congruent\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "===========================================================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "EFGH is a parallelogram -- Given\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "K bisects EG by Theorem 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "EK is congruent to KG by definition of bisector\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "K bisects FH by Theorem 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FK is congruent to KH by definition of bisector\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Angle EKF is congruent to angle HKG by Theorem 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Triangle EFK is congruent to triangle GHK by SAS.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "QED\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |