document.write( "Question 87107This question is from textbook
\n" ); document.write( ": If A is a square matrix with the property (A with an exponet of 2) = 0, show that (I - A)inverse = A + I.\r
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Algebra.Com's Answer #63089 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
Any matrix multiplied by its inverse is equal to the identity matrix, I by definition. So:\r
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\n" ); document.write( "\n" ); document.write( "\"+%28I-A%29%5E%28-1%29%28I-A%29+=+I+\"\r
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\n" ); document.write( "\n" ); document.write( "Post multiply both sides by (I+A):
\n" ); document.write( "\"+%28I-A%29%5E%28-1%29%28I-A%29%28I%2BA%29+=+I%28I%2BA%29+\"\r
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\n" ); document.write( "\n" ); document.write( "now, \"+%28I-A%29%28I%2BA%29+=+I%5E2+%2B+IA+-+AI+-+A%5E2+\"
\n" ); document.write( "\"+%28I-A%29%28I%2BA%29+=+I%5E2+%2B+IA+-+IA+-+A%5E2+\"
\n" ); document.write( "\"+%28I-A%29%28I%2BA%29+=+I+%2B+IA+-+IA+-+A%5E2+\"
\n" ); document.write( "\"+%28I-A%29%28I%2BA%29+=+I+-+A%5E2+\"
\n" ); document.write( "\"+%28I-A%29%28I%2BA%29+=+I+\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"+%28I-A%29%5E%28-1%29%28I-A%29%28I%2BA%29+=+I%28I%2BA%29+\" becomes
\n" ); document.write( "\"+%28I-A%29%5E%28-1%29+=+I%28I%2BA%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and hence \"+%28I-A%29%5E%28-1%29+=+%28I%2BA%29+\"\r
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\n" ); document.write( "Jon
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