document.write( "Question 1014604: A metalworker has a metal alloy that is 20% copper and another alloy that is 60% copper. How many kilograms of each alloy should the metal worker combine to create 80kg of a 44% copper alloy? \n" ); document.write( "
Algebra.Com's Answer #630877 by macston(5194)\"\" \"About 
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\n" ); document.write( "T=amount of 20% alloy; S=amount of 60% alloy
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\n" ); document.write( "T+S=80
\n" ); document.write( "T=80-S
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\n" ); document.write( "0.20T+0.60S=0.44(80)
\n" ); document.write( "0.20(80-S)+0.60S=35.2
\n" ); document.write( "16.0-0.20S+0.60S=35.2
\n" ); document.write( "0.40S=19.2
\n" ); document.write( "S=48
\n" ); document.write( "ANSWER 1: He should use 48 kg of 60% alloy.
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\n" ); document.write( "T=80-S=80-48=32
\n" ); document.write( "ANSWER 2: He should use 32 kg of 20% alloy.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.20T+0.60S=0.44(80)
\n" ); document.write( "0.20(32)+0.60(48)=35.2
\n" ); document.write( "6.4+28.8=35.2
\n" ); document.write( "35.2=35.2
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