document.write( "Question 1014558: Hi outstanding tutors,
\n" ); document.write( "I have a question that is in the quadratic equation solving chapter of my book. It is geometry related, however. Here it is:\r
\n" ); document.write( "\n" ); document.write( "Is it possible for a rectangle with a perimeter of 52 centimeters to have an area of 148.75 square centimeters? Explain. A diagram of the rectangle is given with x representing the with and 26 - x representing the length.
\n" ); document.write( "I know that P=2(l+w) and A=wl. I think somehow a quadratic equation is implemented to solve this. Please help! Thanks!!
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Algebra.Com's Answer #630867 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi outstanding tutors,
\n" ); document.write( "I have a question that is in the quadratic equation solving chapter of my book. It is geometry related, however. Here it is:\r
\n" ); document.write( "\n" ); document.write( "Is it possible for a rectangle with a perimeter of 52 centimeters to have an area of 148.75 square centimeters? Explain. A diagram of the rectangle is given with x representing the with and 26 - x representing the length.
\n" ); document.write( "I know that P=2(l+w) and A=wl. I think somehow a quadratic equation is implemented to solve this. Please help! Thanks!!
\n" ); document.write( "
From your description length = x
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document.write( "Let width be W
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document.write( "Since Perimeter = 52 cm, we get: 2(x + W) = 52______2(x + W) = 2(26)____x + W = 26______W = 26 - x
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document.write( "testing whether or not 148.75 can be the area, we get: x(26 - x) = 148.75
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document.write( "\"26x+-+x%5E2+=+148.75\"
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document.write( "\"x%5E2+-+26x+%2B+148.75+=+0\"
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document.write( "Using the quadratic equation formula, completing the square, or factoring (the trinomial would need to contain all INTEGERS), we find that:
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document.write( "x = 17.5 or x = 8.5, and so, the dimensions of this rectangle would be: , so it's \"highlight_green%28matrix%281%2C2%2CDEFINITELY%2C+POSSIBLE%29%29\" \n" );
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