document.write( "Question 87129:  Ok the problem is functions where the instructions say find f(-3), f(0), f(5)\r
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document.write( "where f(a)=3/4a -1. Im terrible with fractions. I need help in how to understand the solutions which in the back of the book have:\r
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document.write( "-13/4,-1,11/4. i get the answer for f(0) but what about the others. help please. im terrible with fractions. \n" );
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Algebra.Com's Answer #63086 by longjonsilver(2297)    You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so when a=-3 we get: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so now... lets write the 1 as quarters seeing as we have quarters in -9/4. One is 4 quarters --> 4/4 so we get:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so this says -9 quarters -another 4 quarters... that is -13 quarters, written as \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cheers \n" ); document.write( "jon \n" ); document.write( "  |