document.write( "Question 1014558: Hi outstanding tutors,
\n" ); document.write( "I have a question that is in the quadratic equation solving chapter of my book. It is geometry related, however. Here it is:\r
\n" ); document.write( "\n" ); document.write( "Is it possible for a rectangle with a perimeter of 52 centimeters to have an area of 148.75 square centimeters? Explain. A diagram of the rectangle is given with x representing the with and 26 - x representing the length.
\n" ); document.write( "I know that P=2(l+w) and A=wl. I think somehow a quadratic equation is implemented to solve this. Please help! Thanks!!
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Algebra.Com's Answer #630846 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
No, it's not possible. Of the square/rectangular shapes, the square is the one with the largest area (try it, a rectangle 3 by 5 would have a perimeter of 16 and an area of 3*5=15. Now a square 4*4, same perimeter of 16 has an area also 16).
\n" ); document.write( "On that basis, sqrt148.75= 12.20 is each side of our square and the smallest side we can have in order to get the area. And 12.2*4= 48.8 would be the perimeter.
\n" ); document.write( "Your formula would be:
\n" ); document.write( "2x+2(26-x)= 52 Go ahead, knock yourself out. It can't be solved.
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