document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014500>Question 1014500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Karl proposed a project to put up a rectangular garden whose lot perimeter is 36 meters. He was soliciting suggestions  for feasible dimensions of the lot. what will i suggest if i want a maximum lot area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630842 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2 perimeter is 18 meters. <BR>\n" );
document.write( "Since L+W = 18, we can substitute and say L = 18-W and the area, A = (W)(18-W)\r<BR>\n" );
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document.write( "Distributing, we get A= 18W-W^2 which is a parabola, with a shape that opens down. Now, the X intercepts are 0 and 18, which is a fence with no space in between. The vertex, or maximum area occurs at 9, the midpoint between these zeros. \r<BR>\n" );
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document.write( "At 9 x 9 you get an area of 81, \r<BR>\n" );
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document.write( "From this, you should learn that the maximum area you can get given a perimeter of a rectangle is to form a square.  </SPAN>\n" );
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