document.write( "Question 87098: Determine the area of triangle ABC given the following information:
\n" ); document.write( "A=12 B=13 C=15 \n" ); document.write( "
Algebra.Com's Answer #63083 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
Use Hero's Formula:
\n" ); document.write( "s = perimeter / 2
\n" ); document.write( "where
\n" ); document.write( "\"Area+=+sqrt%28s%28s+-+a%29%28s+-+b%29%28s+-+c%29%29\"
\n" ); document.write( "where
\n" ); document.write( "a, b, and c are sides
\n" ); document.write( "~
\n" ); document.write( "s = (12 + 13 + 15) / 2 = (40) / 2 = 20
\n" ); document.write( "\"A+=+sqrt%28s%28s+-+a%29%28s+-+b%29%28s+-+c%29%29\"
\n" ); document.write( "\"A+=+sqrt%2820%2820+-+a%29%2820+-+b%29%2820+-+c%29%29\"
\n" ); document.write( "\"A+=+sqrt%2820%2820+-+12%29%2820+-+13%29%2820+-+15%29%29\"
\n" ); document.write( "\"A+=+sqrt%2820%288%29%287%29%285%29%29\"
\n" ); document.write( "\"A+=+sqrt%28%284%29%285%29%282%29%284%29%287%29%285%29%29\"
\n" ); document.write( "\"A+=+5%2Asqrt%28%284%29%282%29%284%29%287%29%29\"
\n" ); document.write( "\"A+=+10%2Asqrt%28%284%29%282%29%287%29%29\"
\n" ); document.write( "\"A+=+20%2Asqrt%28%282%29%287%29%29\"
\n" ); document.write( "\"A+=+20%2Asqrt%2814%29\" \n" ); document.write( "
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