document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014517>Question 1014517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is twice the second number. The third number is 2 less than thrice the second number. If their sum is 46, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630784 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "F=first number=2S; S=second number; T=third number=3S-2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F+S+T=46<BR>\n" );
document.write( "(2S)+S+(3S-2)=46<BR>\n" );
document.write( "6S-2=46<BR>\n" );
document.write( "6S=48<BR>\n" );
document.write( "S=8<BR>\n" );
document.write( "ANSWER 1: The second number is 8.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "F=2S=2(8)=16<BR>\n" );
document.write( "ANSWER 2: The first number is 16.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "T=3S-2=3(8)-2=24-2=22<BR>\n" );
document.write( "ANSWER 3: The third number is 22.<BR>\n" );
document.write( ".<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );