document.write( "Question 1014331: The areas of two similar rectangles add up to 39 square units. Twice the area of Rectangle A plus one-third the area of Rectangle B equals 33 square units. What are the areas of Rectangles A and B? \n" ); document.write( "
Algebra.Com's Answer #630719 by Theo(13342)\"\" \"About 
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let a be the area of rectangle A.
\n" ); document.write( "let b be the area of rectangle B.\r
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\n" ); document.write( "\n" ); document.write( "a + b = 39
\n" ); document.write( "2a + b/3 = 33\r
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\n" ); document.write( "\n" ); document.write( "multiply the second equation by 3 and keep the first equation the same to get:\r
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\n" ); document.write( "\n" ); document.write( "a + b = 39
\n" ); document.write( "6a + b = 99\r
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\n" ); document.write( "\n" ); document.write( "subtract the second equation from the first to get:\r
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\n" ); document.write( "\n" ); document.write( "-5a = -60\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by -5 to get:\r
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\n" ); document.write( "\n" ); document.write( "a = 12\r
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\n" ); document.write( "\n" ); document.write( "since a + b = 33, then b must be equal to 27\r
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\n" ); document.write( "\n" ); document.write( "area of rectangle A is equal to 12.
\n" ); document.write( "area of rectangle B is equal to 27.\r
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\n" ); document.write( "\n" ); document.write( "a + b = 12 + 27 = 39
\n" ); document.write( "this checks out ok.\r
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\n" ); document.write( "\n" ); document.write( "2a + b/3 = 2*12 + 27/3 = 24 + 9 = 33
\n" ); document.write( "this checks out ok as well.\r
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\n" ); document.write( "\n" ); document.write( "your solution is:\r
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\n" ); document.write( "\n" ); document.write( "area of rectangle A is equal to 12 square units.
\n" ); document.write( "area of rectangle B is equal to 27 square units.
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