document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014422>Question 1014422</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given F(x)=x^2+2x-8 , Solve F(x) Using each method below: Show work please.\r<BR>\n" );
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document.write( "1). Solve by graphing. \r<BR>\n" );
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document.write( "2). Solve for factoring. \r<BR>\n" );
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document.write( "3). Solve by the quadratic formula \r<BR>\n" );
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document.write( "Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630715 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+2x-8=0 <BR>\n" );
document.write( "Factors into (x+4)(x-2)=0; x=-4, 2<BR>\n" );
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document.write( "quadratic <BR>\n" );
document.write( "x=(1/2)(-2 +/- sqrt (4+32)=<BR>\n" );
document.write( "(1/2) (-2+/-6)=(1/2)(-8) and (1/2)(4)=-4,2<BR>\n" );
document.write( "=========<BR>\n" );
document.write( "graph<BR>\n" );
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