document.write( "Question 1014408: 1. Two cars leave town at the same time in opposite directions. One travels 35 km/h and the other 40 km/h. In how many hours will they be 200 km apart?
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document.write( "2. Two cars leave town at the same time in the same direction. One travels 35 mi/h and the other 40 mi/h. In how many hours will they be 15 miles apart?
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document.write( " I can't figure these problems out. It would help out if somebody could help me understand them. My email is alecblake009@hotmail.com \n" );
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Algebra.Com's Answer #630699 by stanbon(75887) ![]() You can put this solution on YOUR website! 1. Two cars leave town at the same time in opposite directions. One travels 35 km/h and the other 40 km/h. In how many hours will they be 200 km apart? \n" ); document.write( "The cars are separating at a rate of 35+40 = 75 km/h \n" ); document.write( "Equation: \n" ); document.write( "time = distance/rate \n" ); document.write( "Ans: time = 200km/75km/h = (200/75)hr = 2 2/3 hrs = 2hr 40min \n" ); document.write( "---------------------------------------- \n" ); document.write( "2. Two cars leave town at the same time in the same direction. One travels 35 mi/h and the other 40 mi/h. In how many hours will they be 15 miles apart? \n" ); document.write( "------ \n" ); document.write( "slower car DATA: distance = 35t, where t is the number of hours \n" ); document.write( "faster car DATA: distance = 40t, \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "faster dist - slower dist = 15 \n" ); document.write( "40t - 35t = 15mi \n" ); document.write( "5t = 15 mi \n" ); document.write( "time = 3 hrs \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------------- \n" ); document.write( " |