document.write( "Question 1014391: *The sum of 5% of one number and 4% of a second number is 44. The sum of 4% of the first number and 5% of the second number is 46. Find the numbers.
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Algebra.Com's Answer #630684 by ikleyn(53763) You can put this solution on YOUR website! . \n" ); document.write( "The sum of 5% of one number and 4% of a second number is 44. \n" ); document.write( "The sum of 4% of the first number and 5% of the second number is 46. Find the numbers. \n" ); document.write( "-------------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "0.05*x + 0.04*y = 44, (1)\r\n" ); document.write( "0.04*x + 0.05*y = 46. (2)\r\n" ); document.write( "\r\n" ); document.write( "Multiply everything by 100. You will get\r\n" ); document.write( "\r\n" ); document.write( "5*x + 4*y = 4400, (1')\r\n" ); document.write( "4*x + 5*y = 4600. (2')\r\n" ); document.write( "\r\n" ); document.write( "Add (1') and (2') and divide by 9. You will get\r\n" ); document.write( "\r\n" ); document.write( "x + y = 1000. (3)\r\n" ); document.write( "\r\n" ); document.write( "Distract (2') from (1'). You will get\r\n" ); document.write( "\r\n" ); document.write( "x - y = -200. (4)\r\n" ); document.write( "\r\n" ); document.write( "Next, add (3) and (4) to get 2x = 1200, x = 600.\r\n" ); document.write( "\r\n" ); document.write( "Now from (3) y = 1000 - 600 = 400.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |