document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014333>Question 1014333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is area of a table tennis ball \r<BR>\n" );
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document.write( "What is the circumference of table tennis ball \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630671 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630671\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diameter of a table tennis ball is ideally set at 40mm(40 millimeters), an actual table tennis ball is allowed to deviate from this ideal diameter by + or - .5mm.  For your problem, I am just using 40mm.<BR>\n" );
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document.write( "a) surface area of sphere (table tennis ball) is calculated by:<BR>\n" );
document.write( "surface area(SA) = 4 *  pi * r^2, where pi = 22/7, r is the radius<BR>\n" );
document.write( "note our radius = 40 / 2 = 20mm<BR>\n" );
document.write( "SA = 4 * (22/7) * 20^2<BR>\n" );
document.write( "SA = 5028.571428571 approx 5028.57mm<BR>\n" );
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document.write( "b) circumference(C) = pi * D where pi = 22/7 and D is the diameter<BR>\n" );
document.write( "C = (22/7) * 40<BR>\n" );
document.write( "c = 125.714285714 approx 125.71mm<BR>\n" );
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