document.write( "Question 87108: This is a long one I know, can someone please help me with this one?\r
\n" ); document.write( "\n" ); document.write( "Use the arithmetic sequence of numbers 2, 4, 6, 8, 10… to find the following:
\n" ); document.write( "a) What is d, the difference between any two consecutive terms?
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\n" ); document.write( "\n" ); document.write( "b) Using the formula for the nth term of an arithmetic sequence, what is 101st term? Answer:
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\n" ); document.write( "\n" ); document.write( "c) Using the formula for the sum of an arithmetic sequence, what is the sum of the first 20 terms?
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\n" ); document.write( "\n" ); document.write( "d) Using the formula for the sum of an arithmetic sequence, what is the sum of the first 30 terms?
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\n" ); document.write( "\n" ); document.write( "e) What observation can you make about the successive partial sums of this sequence (HINT: It would be beneficial to find a few more sums like the sum of the first 2, then the first 3, etc.)?
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Algebra.Com's Answer #63064 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)
\n" ); document.write( "The difference is the factor between each term. So going from 2 to 4, 4 to 6, 6 to 8, and 8 to 10 you see that its adding 2 each time. To verify, pick one term and subtract the previous term from it. So lets say I choose 10: I'm going to subtract 8 from it (which is the previous term) to get a difference of 2. If I pick 8, and subtract 6, I get a difference of 2. \r
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\n" ); document.write( "\n" ); document.write( "So the difference is: d=2\r
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\n" ); document.write( "\n" ); document.write( "b)
\n" ); document.write( "Using what we found earlier, I know that the sequence counts up by 2 each term. So if I'm at 2 (the 1st term) and I go to 4, this means I increase by 2 each term. If I let n=0 then the term is 2, and if I let n=1 then the term is 4. This basically tells me that the arithmetic sequence is 2n+2. To verify, simply plug in the 1st term (n=0) and you'll get 2. Plug in the 2nd term (n=1) you'll get 4, if I let n=2 I get 6, etc. If I wanted to know the 101st term, let n=100 (remember zero is the first term) and it comes to
\n" ); document.write( "\"2%2Ahighlight%28100%29%2B2=202\" So the 101st term is 202\r
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\n" ); document.write( "\n" ); document.write( "c)Now lets find the sum of the first 20 terms\r
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\n" ); document.write( "\n" ); document.write( "Using the sum of arithmetic series formula:
\n" ); document.write( "\"s=%28n%2F2%29%2A%28a%5B1%5D%2Ba%5Bn%5D%29\" a[1]=first term, a[n]=nth term (ending term which is the 20th term), and n is the number of terms\r
\n" ); document.write( "\n" ); document.write( "Since we know the first term is 2, we know that \"a%5B1%5D=2\". \r
\n" ); document.write( "\n" ); document.write( "So lets calculate the 20th term. \r
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\n" ); document.write( "\n" ); document.write( "Let n=19(remember we started at n=0)\r
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\n" ); document.write( "\n" ); document.write( "\"a%5B19%5D=2%2819%29%2B2=38%2B2=40\"\r
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\n" ); document.write( "\n" ); document.write( "So the term \"a%5Bn%5D=40\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets evaluate the sum\r
\n" ); document.write( "\n" ); document.write( "\"s=%2820%2F2%29%2A%282%2B40%29\" Plug in values.
\n" ); document.write( "\"s=%2810%29%2A%2842%29\"Simplify
\n" ); document.write( "\"s=420\" So the sum of the first 20 terms is 420.\r
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\n" ); document.write( "\n" ); document.write( "d)Now lets find the sum of the first 30 terms\r
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\n" ); document.write( "\n" ); document.write( "Using the sum of arithmetic series formula:
\n" ); document.write( "\"s=%28n%2F2%29%2A%28a%5B1%5D%2Ba%5Bn%5D%29\" a[1]=first term, a[n]=nth term (ending term which is the 30th term), and n is the number of terms\r
\n" ); document.write( "\n" ); document.write( "Since we know the first term is 2, we know that \"a%5B1%5D=2\". \r
\n" ); document.write( "\n" ); document.write( "So lets calculate the 30th term. \r
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\n" ); document.write( "\n" ); document.write( "Let n=29(remember we started at n=0)\r
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\n" ); document.write( "\n" ); document.write( "\"a%5B19%5D=2%2829%29%2B2=38%2B2=60\"\r
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\n" ); document.write( "\n" ); document.write( "So the term \"a%5Bn%5D=60\"\r
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\n" ); document.write( "\n" ); document.write( "Now lets evaluate the sum\r
\n" ); document.write( "\n" ); document.write( "\"s=%2830%2F2%29%2A%282%2B60%29\" Plug in values.
\n" ); document.write( "\"s=%2815%29%2A%2862%29\"Simplify
\n" ); document.write( "\"s=930\" So the sum of the first 30 terms is 930.\r
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\n" ); document.write( "\n" ); document.write( "e)\r
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\n" ); document.write( "\n" ); document.write( "Sum of the first 2 terms
\n" ); document.write( "2+4=6
\n" ); document.write( "Sum of the first 3 terms
\n" ); document.write( "2+4+6=12
\n" ); document.write( "Sum of the first 4 terms
\n" ); document.write( "2+4+6+8=20
\n" ); document.write( "Sum of the first 5 terms
\n" ); document.write( "2+4+6+8+10=30
\n" ); document.write( "Sum of the first 6 terms
\n" ); document.write( "2+4+6+8+10+12=42
\n" ); document.write( "Sum of the first 7 terms
\n" ); document.write( "2+4+6+8+10+12+14=56
\n" ); document.write( "Sum of the first 8 terms
\n" ); document.write( "2+4+6+8+10+12+14+16=72
\n" ); document.write( "Sum of the first 9 terms
\n" ); document.write( "2+4+6+8+10+12+14+16+18=90
\n" ); document.write( "Sum of the first 10 terms
\n" ); document.write( "2+4+6+8+10+12+14+16+18+20=110\r
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\n" ); document.write( "\n" ); document.write( "Notice how the first sum (which is 6) can be factored like this:
\n" ); document.write( "6=2*3\r
\n" ); document.write( "\n" ); document.write( "Notice how the second sum (which is 12) can be factored like this:
\n" ); document.write( "12=3*4\r
\n" ); document.write( "\n" ); document.write( "Notice how the third sum (which is 20) can be factored like this:
\n" ); document.write( "20=4*5\r
\n" ); document.write( "\n" ); document.write( "Notice how the fourth sum (which is 30) can be factored like this:
\n" ); document.write( "30=5*6\r
\n" ); document.write( "\n" ); document.write( "Notice how the fifth sum (which is 42) can be factored like this:
\n" ); document.write( "42=6*7\r
\n" ); document.write( "\n" ); document.write( "Notice how the sixth sum (which is 56) can be factored like this:
\n" ); document.write( "56=7*8\r
\n" ); document.write( "\n" ); document.write( "Notice how the seventh sum (which is 72) can be factored like this:
\n" ); document.write( "72=8*9\r
\n" ); document.write( "\n" ); document.write( "Notice how the eighth sum (which is 90) can be factored like this:
\n" ); document.write( "90=9*10\r
\n" ); document.write( "\n" ); document.write( "Notice how the ninth sum (which is 110) can be factored like this:
\n" ); document.write( "110=10*11\r
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\n" ); document.write( "\n" ); document.write( "and this pattern continues...\r
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\n" ); document.write( "\n" ); document.write( "Basically, every sum of this sequence can be factored into two numbers in which the second number is one more than the first number\r
\n" ); document.write( "\n" ); document.write( "So each sum follows the sequence \"n%28n%2B1%29\" \r
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\n" ); document.write( "\n" ); document.write( "Notice if we let \"n=2\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"2%282%2B1%29=2%2A3=6\"\r
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\n" ); document.write( "\n" ); document.write( "which is one of our sums. \r
\n" ); document.write( "\n" ); document.write( "Notice if we let \"n=3\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"3%283%2B1%29=3%2A4=12\"\r
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\n" ); document.write( "\n" ); document.write( "which is also one of the sums\r
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\n" ); document.write( "\n" ); document.write( "So this helps verify our sequence
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