document.write( "Question 87074: I don't know where to begin with this problem!! Please help. Thanks you. \r
\n" ); document.write( "\n" ); document.write( "A candle is lit at 5:30 p.m. Another candle, 1 cm shorter than the first, is lit at 7 p.m. The candles are the same length at 9:30 p.m. The first candle burns out at 11:30 p.m. and the second one at 11:00 p.m. How tall was the longer candle?
\n" ); document.write( "

Algebra.Com's Answer #63062 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Each candle has a rate of burn, and what is being assumed in
\n" ); document.write( "the problem (and of course is debateable) is that the rate of
\n" ); document.write( "burn for each is constant and may be different for each candle.
\n" ); document.write( "The rate of burn is how far it burns down in a given time period.
\n" ); document.write( "First look at when each is lit and when it burns out.
\n" ); document.write( "Call the 1st one candle A and the 2nd one candle B.
\n" ); document.write( "The rate of burn for A is \"r%5BA%5D\"
\n" ); document.write( "The rate of burn for B is \"r%5BB%5D\"
\n" ); document.write( "Call \"h\" the starting height of A in cm
\n" ); document.write( "The \"h-1\" is the starting height of B in cm
\n" ); document.write( "From 5:30 to 11:30 for A is 6 hours
\n" ); document.write( "From 7:00 to 11:00 for B is 4 hours
\n" ); document.write( "\"r%5BA%5D+=+h%2F6\"
\n" ); document.write( "\"r%5BB%5D+=+%28h-1%29%2F4\"
\n" ); document.write( "Now look at the information relating to the candles being the same
\n" ); document.write( "height at 9:30. Candle A will burn down the same amount as B plus an
\n" ); document.write( "extra cm.
\n" ); document.write( "So, in words, (A's rate)(A's time) = (B's rate)(B's time) + 1 cm
\n" ); document.write( "A's time is 4 hrs, and B's time is 2.5 hours
\n" ); document.write( "\"4%28h%2F6%29+=+2.5%28%28h-1%29%2F4%29+%2B+1\"
\n" ); document.write( "multiple both sides by LCD which is 12
\n" ); document.write( "\"+8h+=+3%2A2.5%28h-1%29+%2B+12\"
\n" ); document.write( "\"8h+=+%2815%2F2%29%2A%28h-1%29+%2B+12\"
\n" ); document.write( "multiply both sides by 2
\n" ); document.write( "\"16h+=+15h+-+15+%2B+24\"
\n" ); document.write( "\"h+=+9\"
\n" ); document.write( "So, the height of the longest candle is 9 cm
\n" ); document.write( "Check this by plugging back into equations
\n" ); document.write( "What are the rates of A and B?
\n" ); document.write( "\"r%5BA%5D+=+h%2F6\"
\n" ); document.write( "\"r%5BA%5D+=+9%2F6\"
\n" ); document.write( "\"r%5BA%5D+=+3%2F2\"
\n" ); document.write( "\"r%5BB%5D+=+%28h-1%29%2F4\"
\n" ); document.write( "\"r%5BB%5D+=+8%2F4\"
\n" ); document.write( "\"r%5BB%5D+=+2\"
\n" ); document.write( "\"4%28h%2F6%29+=+2.5%28%28h-1%29%2F4%29+%2B+1\"
\n" ); document.write( "\"4%283%2F2%29+=+2.5%2A2+%2B+1\"
\n" ); document.write( "\"6+=+5+%2B+1\"
\n" ); document.write( "\"6+=+6\"
\n" ); document.write( "How about the rate*time for each to burn all the way down?
\n" ); document.write( "\"6%28h%2F6%29+=+4%28%28h-1%29%2F4%29+%2B+1\"
\n" ); document.write( "h = 9
\n" ); document.write( "\"9+=+4%2A2+%2B+1\"
\n" ); document.write( "\"9+=+8+%2B+1\"
\n" ); document.write( "\"9+=+9\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );