document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014243>Question 1014243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following questions concern a circle of radius 4 cm.<BR>\n" );
document.write( "a) Determine the area of the sector of a circle that subtends an angle of 2&#960;/3 radians.<BR>\n" );
document.write( "b) Determine the angle at the centre of the circle that is subtended by an arc 2 cm long. Express your answer in terms of &#960; radians accurate to 2 decimal places.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630562 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The following questions concern a circle of radius 4 cm.<BR>\n" );
document.write( "a) Determine the area of the sector of a circle that subtends an angle of 2&#960;/3 radians.<BR>\n" );
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document.write( "Area of the whole circle:: pi*4^2 = 16pi<BR>\n" );
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document.write( "2pi/3 is (1/3)2pi, so the area is (1/3)(16pi) = (5 1/3)pi<BR>\n" );
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document.write( "b) Determine the angle at the centre of the circle that is subtended by an arc 2 cm long. Express your answer in terms of &#960; radians accurate to 2 decimal places.\r<BR>\n" );
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document.write( "theta (in radians) = (arc length)/(radius)<BR>\n" );
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document.write( "Your Problem: <BR>\n" );
document.write( "theta = (2 cm)/r = (2cm)/(4cm) = 0.50 radian<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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