document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014258>Question 1014258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jason's age is 3 times Shauna's present age. In 4 years' time, the sum of their ages will be 56. Find their present ages.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630560 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Now, J=3S\r<BR>\n" );
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document.write( "In 4 years, (J+4)+(S+4)=56\r<BR>\n" );
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document.write( "Easy substitution, <BR>\n" );
document.write( "(3S+4)+(S+4)=56   (You see - since J=3S I just replaced J with 3S)\r<BR>\n" );
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document.write( "4S+8=56\r<BR>\n" );
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document.write( "4S = 48\r<BR>\n" );
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document.write( "S=12, J=36 now Jason is 3X Shauna's age. In 4 years he is 40 and she is 16, they sum to 56.  </SPAN>\n" );
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