document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014175>Question 1014175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The smaller of the complementary angles is 12 less than the larger angle. Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630532 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The smaller of the complementary angles is 12 less than the larger angle. Find the measure of the angles<BR>\n" );
document.write( "    let x= larger of the complementary angles<BR>\n" );
document.write( "   x-12=smaller of the complementary angles<BR>\n" );
document.write( "x+x-12=90<BR>\n" );
document.write( "2x=78<BR>\n" );
document.write( "x=39<BR>\n" );
document.write( "x+12=51<BR>\n" );
document.write( "larger of the complementary angles=51º<BR>\n" );
document.write( "smaller of the complementary angles=39º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );