document.write( "Question 1014187: AB is a chord of a circle, centre O, with radius 17cm.If AB=16cm, find the distance of O from AB.
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Algebra.Com's Answer #630526 by ikleyn(52797)\"\" \"About 
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\n" ); document.write( "AB is a chord of a circle, centre O, with radius 17cm.If AB=16cm, find the distance of O from AB.
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document.write( "Draw the perpendicular from the center O to the cord AB, and let the point C represents its intersection with the chord AB.\r\n" );
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document.write( "The length |OC| is the distance of interest, d.\r\n" );
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document.write( "Notice that the point C bisects the chord AB. It is because the triangle OAB is isosceles having congruent sizes OA and OB (radii).\r\n" );
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document.write( "Now from the right-angled triangle OAC you have \r\n" );
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document.write( "d = \"sqrt%28abs%28OC%29%5E2+-+%28%28abs%28AC%29%29%2F2%29%5E2%29\" = \"sqrt%2817%5E2+-+8%5E2%29\" = \"sqrt%28289+-+64%29\" = \"sqrt%28225%29\" = 15.\r\n" );
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document.write( "Thus the distance d is 15 cm.\r\n" );
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document.write( "Answer. The distance of O from AB is 15 cm.\r\n" );
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