document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1014129>Question 1014129</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x)=5x^2+50X+123 1/5 has a root at x=-4 2/5 , use the axis of symmetry to find the other root of the function. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630505 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5x^2+50x+123<BR>\n" );
document.write( "vertex x value is -b/2a<BR>\n" );
document.write( "vertex is -5 for x<BR>\n" );
document.write( "y is -2<BR>\n" );
document.write( "(-5,-1.8) is vertex.<BR>\n" );
document.write( "symmetrical around x= -5<BR>\n" );
document.write( "from vertex to one root x changes by +3/5, y changes plus 1.8<BR>\n" );
document.write( "from vertex to other root x changes by -3/5, y changes plus 1.8 (-5.6,0)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C200%2C-6%2C-4%2C-10%2C10%2C5x%5E2%2B50x%2B123%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C200%2C-6%2C-4%2C-10%2C10%2C5x%5E2%2B50x%2B123%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );