document.write( "Question 1014127: One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?\r
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Algebra.Com's Answer #630499 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. \n" ); document.write( "Change these ratios to percent salt in decimal form \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water? \n" ); document.write( "Change to percent salt \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Let x = amt of 37.5 % salt \n" ); document.write( "then \n" ); document.write( "(280-x) = amt of 20% salt \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( ".375x + .20(280-x) = .30(280) \n" ); document.write( ".375x + 56 - .20x = 84 \n" ); document.write( ".375x - .20x = 84 - 56 \n" ); document.write( ".175x = 28 \n" ); document.write( "x = 28/.175 \n" ); document.write( "x = 160 qts of the 3:5 solution \n" ); document.write( "and \n" ); document.write( "280 - 160 = 120 qts of the 2:8 solution \n" ); document.write( " \n" ); document.write( " |