document.write( "Question 1014127: One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water. How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?\r
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Algebra.Com's Answer #630499 by ankor@dixie-net.com(22740)\"\" \"About 
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One solution contains 2 parts salt to 8 parts water, and another contains 3 parts salt to 5 parts water.
\n" ); document.write( "Change these ratios to percent salt in decimal form
\n" ); document.write( "\"2%2F%28%282%2B8%29%29\" = .20 salt
\n" ); document.write( "and
\n" ); document.write( "\"3%2F%28%283%2B5%29%29\" = .375 salt
\n" ); document.write( ":
\n" ); document.write( " How much of each should be mixed together in order to obtain 280 quarts of a solution that is 3 parts salt to 7 parts water?
\n" ); document.write( "Change to percent salt
\n" ); document.write( "\"3%2F%28%283%2B7%29%29\" = .30 salt
\n" ); document.write( ":
\n" ); document.write( "Let x = amt of 37.5 % salt
\n" ); document.write( "then
\n" ); document.write( "(280-x) = amt of 20% salt
\n" ); document.write( ":
\n" ); document.write( "A typical mixture equation
\n" ); document.write( ".375x + .20(280-x) = .30(280)
\n" ); document.write( ".375x + 56 - .20x = 84
\n" ); document.write( ".375x - .20x = 84 - 56
\n" ); document.write( ".175x = 28
\n" ); document.write( "x = 28/.175
\n" ); document.write( "x = 160 qts of the 3:5 solution
\n" ); document.write( "and
\n" ); document.write( "280 - 160 = 120 qts of the 2:8 solution
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