document.write( "Question 1014141: I am trying to determine the diameter of a cylinder with the requirement that the diameter at one end is 10% larger than the smaller end. How do I calculate it if the length of the cylinder is equal to larger diameter or if the length of the cylinder varies from half to triple the diameter?\r
\n" ); document.write( "\n" ); document.write( "for example R1 = 10 R2 = x h = 10
\n" ); document.write( " R1 = 10 R2 = X h = 5
\n" ); document.write( " R1 = 10 R2 = x h = 18
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Algebra.Com's Answer #630493 by ikleyn(52790)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "I am trying to determine the diameter of a cylinder with the requirement that the diameter at one end is 10% larger
\n" ); document.write( "than the smaller end. How do I calculate it if the length of the cylinder is equal to larger diameter or if the length
\n" ); document.write( "of the cylinder varies from half to triple the diameter?\r
\n" ); document.write( "\n" ); document.write( "for example R1 = 10 R2 = x h = 10
\n" ); document.write( " R1 = 10 R2 = X h = 5
\n" ); document.write( " R1 = 10 R2 = x h = 18
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document.write( "Hello,\r\n" );
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document.write( "your body is not a cylinder.\r\n" );
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document.write( "Your body is a cone. More exactly, a truncated cone.\r\n" );
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document.write( "If you want the greater diameter be in 10% larger than the smaller diameter, then take D = 1.1*d, \r\n" );
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document.write( "where D is the greater diameter, and d = is a smaller diameter.\r\n" );
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\n" ); document.write( "Comment from student: Thank you for your answer, however it doesn't answer the full question.
\n" ); document.write( "If the cone is 10 inches in height and the large end is 10 inches the smaller end is 9 inches if the large end is 10 inches
\n" ); document.write( "and the cone is 20 inches the smaller end is ?
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document.write( "My response: Your comment sounds as if it are you examine me.\r\n" );
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document.write( "It is not so.\r\n" );
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document.write( "Please make an effort and solve it yourself. It is so easy.\r\n" );
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