document.write( "Question 1014099: Waseem score 30% of the marks in an exam,and fails by 60 marks.Waqar scores 40% of the marks in the same exam and passes by 20 marks .What is the maximum number of marks in this exam? \n" ); document.write( "
Algebra.Com's Answer #630463 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Waseem score 30% of the marks in an exam,and fails by 60 marks. \ \n" ); document.write( "Waqar scores 40% of the marks in the same exam and passes by 20 marks .\ \n" ); document.write( "What is the maximum number of marks in this exam? \n" ); document.write( ": \n" ); document.write( "let m = maximum marks on the exam \n" ); document.write( "let p = no. of marks required to pass \n" ); document.write( ": \n" ); document.write( "\" Waseem score 30% of the marks in an exam,and fails by 60 marks.\" \n" ); document.write( ".3m = p - 60 \n" ); document.write( "\" Waqar scores 40% of the marks in the same exam and passes by 20 marks \" \n" ); document.write( ".4m = p + 20 \n" ); document.write( ": \n" ); document.write( "Use elimination here \n" ); document.write( "Subtract the 1st equation from the 2nd equation \n" ); document.write( ".4m = p + 20 \n" ); document.write( ".3m = p - 60 \n" ); document.write( "-------------subtraction eliminates p, find m \n" ); document.write( ".1m = 80 \n" ); document.write( "m = 80/.1 \n" ); document.write( "m = 800 is the maximum number of marks \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out, find p \n" ); document.write( ".4(800) = p + 20 \n" ); document.write( "320 - 20 = p \n" ); document.write( "p = 300 is passing \n" ); document.write( "See if that works in the 1st equation; .3m = p - 60 \n" ); document.write( ".3(800) = 300 - 60 \n" ); document.write( "240 = 240, confirms our solution \n" ); document.write( " \n" ); document.write( " |