document.write( "Question 1014045: In the morning, Maria drove to a business appointment at 70 mph. Her average speed on the return trip in the afternoon was 60 mph. The return trip took 1/6
\n" ); document.write( "hr longer because of heavy traffic. How far did she travel to the appointment? \n" ); document.write( "

Algebra.Com's Answer #630383 by fractalier(6550) $\"\"$ $\"About$

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Since rate times time equals distance...we can call the time on the first trip t...the return trip would take t + 1/6...we can write
\n" ); document.write( "70t = 60(t + 1/6)
\n" ); document.write( "70t = 60t + 10
\n" ); document.write( "10t = 10
\n" ); document.write( "t = 1 hour
\n" ); document.write( "Therefore the trip was 70 miles long, each way. \n" ); document.write( "

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