document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013971>Question 1013971</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cary is 8 years older than Dan. In 10 years the sum of their ages will be 102. Find the age of each man now. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630327 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call their ages NOW, c and d. Then we have<BR>\n" );
document.write( "c = d + 8<BR>\n" );
document.write( "In 10 years,<BR>\n" );
document.write( "(c+10) + (d+10) = 102<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "(d+8+10) + (d+10) = 102<BR>\n" );
document.write( "2d + 28 = 102<BR>\n" );
document.write( "2d = 74<BR>\n" );
document.write( "d = 37<BR>\n" );
document.write( "c = 45 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );