document.write( "Question 1013999: 4.5\r
\n" ); document.write( "\n" ); document.write( "Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35\r
\n" ); document.write( "\n" ); document.write( "The solution set is { }\r
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\n" ); document.write( "\n" ); document.write( "I got 1,5,7 is this right?
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Algebra.Com's Answer #630322 by Alan3354(69443)\"\" \"About 
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Solve the equation x^3 -13x^2 +47x-35=0 given that 1 is a zero of f(x)=x^3 -13x^2 +47x-35
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\n" ); document.write( "I got 1,5,7 is this right?
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\n" ); document.write( "It's right.
\n" ); document.write( "You can check it.
\n" ); document.write( "If (x-1)*(x-5)*(x-7) = x^3 -13x^2 +47x-35 it's right.
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\n" ); document.write( "f(x) = x^3 -13x^2 +47x-35
\n" ); document.write( "If f(1) = 0 it's a zero.
\n" ); document.write( "Same for f(5) and f(7).
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