document.write( "Question 1013998: 4.1\r
\n" ); document.write( "\n" ); document.write( "Find the coordinates of the vertex for the parabola defined by the given quadratic function.\r
\n" ); document.write( "\n" ); document.write( "f(x) =-4(x+3)^2 +6\r
\n" ); document.write( "\n" ); document.write( "The vertex is: (type an ordered pair)\r
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\n" ); document.write( "\n" ); document.write( "The answer I got was (-3,6) is this right? \n" ); document.write( "
Algebra.Com's Answer #630320 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "When the quadratic function, f(x) is given as the equation of a\r\n" );
document.write( "parabola in the form\r\n" );
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document.write( "f(x) = a(x-h)² + k\r\n" );
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document.write( "then the vertex of the parabola is (h,k)\r\n" );
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document.write( "Your function is\r\n" );
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document.write( "f(x) = -4(x+3)² + 6\r\n" );
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document.write( "So -h = +3 and h = -3 and k = 6, so the vertex is\r\n" );
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document.write( "(h,k) = (-3,6).\r\n" );
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document.write( "So you are correct.\r\n" );
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document.write( "Edwin
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