document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1013961>Question 1013961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I get 12 coins to equal 85 cents? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #630271 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39623)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=630271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Maybe, more than one answer.  A practical way is start with as few coins as possible, and start breaking then one at a time.\r<BR>\n" );
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document.write( "Using their values in cents,\r<BR>\n" );
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document.write( "25, 25, 25, 5, 5 ----- only five coins;\r<BR>\n" );
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document.write( "25, 25, 5(5), 2*(5) -------- nine coins;\r<BR>\n" );
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document.write( "25, 10,5,5,5, 5(5), 2(5) --------twelve coins.\r<BR>\n" );
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document.write( "One quarter<BR>\n" );
document.write( "One dime,<BR>\n" );
document.write( "Ten nickles </SPAN>\n" );
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