document.write( "Question 1013952: A salesman drives from Ajax to Barrington, a distance of 122 mi, at a steady speed. He then increases his speed by 14 mi/h to drive the 172 mi from Barrington to Collins. If the second leg of his trip took 10 min more time than the first leg, how fast was he driving between Ajax and Barrington? \n" ); document.write( "
Algebra.Com's Answer #630264 by josgarithmetic(39620)\"\" \"About 
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document.write( "                         rate         time        distance\r\n" );
document.write( "Ajax to Barr.            r             t           122\r\n" );
document.write( "Barrinton to Cols.       r+14         t+1/6        172\r\n" );
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\n" ); document.write( "\n" ); document.write( "Be sure the data table makes sense to you.\r
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\n" ); document.write( "\n" ); document.write( "RT=D, basic relationship;
\n" ); document.write( "\"system%28rt=122%2C%28r%2B14%29%28t%2B1%2F6%29=172%29\", find r.\r
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\n" ); document.write( "\n" ); document.write( "You should know what to do from there.\r
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\n" ); document.write( "Substitute for t using t=122/r, and simplify through the algebra steps, and you should have a step, \"r%5E2-286r%2B10248=0\".
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